Integrand size = 37, antiderivative size = 54 \[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=\frac {(1-a x)^{-\frac {1}{2} n (1+n)} (1+a x)^{\frac {1}{2} (1-n) n} (1-a n x)}{a^3 n \left (1-n^2\right )} \]
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Time = 0.01 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.027, Rules used = {82} \[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=\frac {(1-a x)^{-\frac {1}{2} n (n+1)} (a x+1)^{\frac {1}{2} (1-n) n} (1-a n x)}{a^3 n \left (1-n^2\right )} \]
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Rule 82
Rubi steps \begin{align*} \text {integral}& = \frac {(1-a x)^{-\frac {1}{2} n (1+n)} (1+a x)^{\frac {1}{2} (1-n) n} (1-a n x)}{a^3 n \left (1-n^2\right )} \\ \end{align*}
Time = 0.25 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.91 \[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=\frac {(1-a x)^{-\frac {1}{2} n (1+n)} (1+a x)^{-\frac {1}{2} (-1+n) n} (-1+a n x)}{a^3 n \left (-1+n^2\right )} \]
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Time = 0.91 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.96
method | result | size |
gosper | \(\frac {\left (a x +1\right )^{-\frac {1}{2} n^{2}+\frac {1}{2} n} \left (a n x -1\right ) \left (-a x +1\right )^{-\frac {1}{2} n^{2}-\frac {1}{2} n}}{a^{3} n \left (n^{2}-1\right )}\) | \(52\) |
risch | \(-\frac {\left (-a x +1\right )^{-1-\frac {1}{2} n^{2}-\frac {1}{2} n} \left (a^{3} x^{3} n -a^{2} x^{2}-a n x +1\right ) \left (a x +1\right )^{-1-\frac {1}{2} n^{2}+\frac {1}{2} n}}{n \left (n^{2}-1\right ) a^{3}}\) | \(72\) |
parallelrisch | \(-\frac {\left (a x +1\right )^{-1-\frac {1}{2} n^{2}+\frac {1}{2} n} \left (-a x +1\right )^{-1-\frac {1}{2} n^{2}-\frac {1}{2} n} x^{3} a^{3} n -x^{2} \left (-a x +1\right )^{-1-\frac {1}{2} n^{2}-\frac {1}{2} n} \left (a x +1\right )^{-1-\frac {1}{2} n^{2}+\frac {1}{2} n} a^{2}-\left (a x +1\right )^{-1-\frac {1}{2} n^{2}+\frac {1}{2} n} x \left (-a x +1\right )^{-1-\frac {1}{2} n^{2}-\frac {1}{2} n} a n +\left (-a x +1\right )^{-1-\frac {1}{2} n^{2}-\frac {1}{2} n} \left (a x +1\right )^{-1-\frac {1}{2} n^{2}+\frac {1}{2} n}}{a^{3} n \left (n^{2}-1\right )}\) | \(171\) |
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Time = 0.24 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.37 \[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=-\frac {{\left (a^{3} n x^{3} - a^{2} x^{2} - a n x + 1\right )} {\left (a x + 1\right )}^{-\frac {1}{2} \, n^{2} + \frac {1}{2} \, n - 1} {\left (-a x + 1\right )}^{-\frac {1}{2} \, n^{2} - \frac {1}{2} \, n - 1}}{a^{3} n^{3} - a^{3} n} \]
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Leaf count of result is larger than twice the leaf count of optimal. 425 vs. \(2 (41) = 82\).
Time = 65.02 (sec) , antiderivative size = 425, normalized size of antiderivative = 7.87 \[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=\begin {cases} \frac {x^{3}}{3} & \text {for}\: a = 0 \\- \frac {a x \log {\left (x - \frac {1}{a} \right )}}{4 a^{4} x + 4 a^{3}} - \frac {3 a x \log {\left (x + \frac {1}{a} \right )}}{4 a^{4} x + 4 a^{3}} - \frac {\log {\left (x - \frac {1}{a} \right )}}{4 a^{4} x + 4 a^{3}} - \frac {3 \log {\left (x + \frac {1}{a} \right )}}{4 a^{4} x + 4 a^{3}} - \frac {2}{4 a^{4} x + 4 a^{3}} & \text {for}\: n = -1 \\- \frac {x}{a^{2}} - \frac {\log {\left (x - \frac {1}{a} \right )}}{2 a^{3}} + \frac {\log {\left (x + \frac {1}{a} \right )}}{2 a^{3}} & \text {for}\: n = 0 \\\frac {3 a x \log {\left (x - \frac {1}{a} \right )}}{4 a^{4} x - 4 a^{3}} + \frac {a x \log {\left (x + \frac {1}{a} \right )}}{4 a^{4} x - 4 a^{3}} - \frac {3 \log {\left (x - \frac {1}{a} \right )}}{4 a^{4} x - 4 a^{3}} - \frac {\log {\left (x + \frac {1}{a} \right )}}{4 a^{4} x - 4 a^{3}} - \frac {2}{4 a^{4} x - 4 a^{3}} & \text {for}\: n = 1 \\- \frac {a^{3} n x^{3} \left (- a x + 1\right )^{- \frac {n^{2}}{2} - \frac {n}{2} - 1} \left (a x + 1\right )^{- \frac {n^{2}}{2} + \frac {n}{2} - 1}}{a^{3} n^{3} - a^{3} n} + \frac {a^{2} x^{2} \left (- a x + 1\right )^{- \frac {n^{2}}{2} - \frac {n}{2} - 1} \left (a x + 1\right )^{- \frac {n^{2}}{2} + \frac {n}{2} - 1}}{a^{3} n^{3} - a^{3} n} + \frac {a n x \left (- a x + 1\right )^{- \frac {n^{2}}{2} - \frac {n}{2} - 1} \left (a x + 1\right )^{- \frac {n^{2}}{2} + \frac {n}{2} - 1}}{a^{3} n^{3} - a^{3} n} - \frac {\left (- a x + 1\right )^{- \frac {n^{2}}{2} - \frac {n}{2} - 1} \left (a x + 1\right )^{- \frac {n^{2}}{2} + \frac {n}{2} - 1}}{a^{3} n^{3} - a^{3} n} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.17 \[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=\frac {{\left (a n x - 1\right )} e^{\left (-\frac {1}{2} \, n^{2} \log \left (a x + 1\right ) - \frac {1}{2} \, n^{2} \log \left (-a x + 1\right ) + \frac {1}{2} \, n \log \left (a x + 1\right ) - \frac {1}{2} \, n \log \left (-a x + 1\right )\right )}}{{\left (n^{3} - n\right )} a^{3}} \]
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\[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=\int { {\left (a x + 1\right )}^{-\frac {1}{2} \, {\left (n - 1\right )} n - 1} {\left (-a x + 1\right )}^{-\frac {1}{2} \, {\left (n + 1\right )} n - 1} x^{2} \,d x } \]
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Time = 1.63 (sec) , antiderivative size = 140, normalized size of antiderivative = 2.59 \[ \int x^2 (1-a x)^{-1-\frac {1}{2} n (1+n)} (1+a x)^{-1-\frac {1}{2} (-1+n) n} \, dx=-\frac {\frac {x^3}{\left (n^2-1\right )\,{\left (a\,x+1\right )}^{\frac {n\,\left (n-1\right )}{2}+1}}-\frac {x}{a^2\,\left (n^2-1\right )\,{\left (a\,x+1\right )}^{\frac {n\,\left (n-1\right )}{2}+1}}+\frac {1}{a^3\,n\,\left (n^2-1\right )\,{\left (a\,x+1\right )}^{\frac {n\,\left (n-1\right )}{2}+1}}-\frac {x^2}{a\,n\,\left (n^2-1\right )\,{\left (a\,x+1\right )}^{\frac {n\,\left (n-1\right )}{2}+1}}}{{\left (1-a\,x\right )}^{\frac {n\,\left (n+1\right )}{2}+1}} \]
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